cameroon gce A level 2024 automatic control of electrical machines 2

cameroon gce A level 2024 automatic control of electrical machines 2

cameroon gce A level 2024 automatic control of electrical machines 2

1. Direct current machine
For a given direct current machines, we have the following:
Field
resistance: 200£}.
Armature resistance: 0.8Q.
Nominal values are indicated by the manufacturer: supply voltage: U ~ 120V; armature current
rotation 2400
tr/min for an excitation of 120V.
The machine been separately excited
, we supply separately the field Vvith a 120V.
a) Calculate the field excited current.
b)
Determine the value of the starting rheostat needed to limit the starting current at 1
c
) Calculate under nominal conditions:
i) The back emf
ii) The total mechanical power developed and the value ot the nominal torque.
la 10A; speed of
(2 marks)
.5 In. (2 marks)
(2 marks)
(
4 marks)
2. Three Phase Asynchronous Motor > , ^
A three phase Asynchronous cage motor of 220/380V, is supply from a 127/220V, 50Hz network. The resistance
measure between two stator phases is 3.5£2. On Noload test: the motor rotates at a frequency Ns practically equal to
3000rev/min and the two wattmeter method gave the following indications: P|=460W, ?2= 260W. The line current is
3.32
A.
( 1 mark)
( 1 mark)
a) How are the motor winding coupled?
b) What is the number of poles in the motor stator? .
c) Calculate:
i) The power absorbed. .
.
ii) The noload power factor
iii) The stator copper losses.
d What is the value of the rotor copper losses under this condition? Explain,
e) Calculate the magnetic losses Pm, knowing that the mechanical loss amount to 20W.
( 1 mark)
( 1 mark)
(2 marks)
(2 marks)
(2 marks
)
3. SinglePhase Transformer

and X1=5.2Cl , X2=0.015£2 respectively Calculate for the transformer:
a) Equivalent resistance referred
to the primary.
b) Equivalent resistance referred to the secondary.
c) Equivalent reactance referred to both primary and secondary.
d
) Equivalent impedance referred to both primary and secondary.
e) Total copper losses using individual winding
resistances
f) Total copper losses using referred resistances.
(1.5 mark)
(
1 mark)
(2 marks
)
(1.5 marks)
(2.5 marks)
(1.5 marks
)

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