Advanced level 2025 BAEBOC Pure mathematics with mechanics guide
Advanced level 2025 BAEBOC Pure mathematics with mechanics guide
Here’s the extracted data from the image:
i)
ii) a)
b)
Advanced level 2025 BAEBOC Pure mathematics with mechanics guide
Here’s the extracted data from the image:
i) 4x−10ydxdy=3xdxdy+3y ⇒dxdy=3x+10y4x−3y
mT=3(−2)+10(2)4(−2)−3(2)=−6+20−8−6=14−14=−1
y−2=−1(x−(−2))⇒y−2=−x−2⇒y=−x
ii) a) y=(cos(x1/2
))2 dxdy=2cos(x1/2)⋅(−sin(x1/2))⋅21x−1/2=−x
b) y=ln[1−x2sin4x]3=3ln(1−x2sin4x)=3(4ln∣sinx∣−ln∣1−x2∣)=12ln∣sinx∣−3ln∣1−x2∣ dxdy=12sinxcosx−31−x2−2x=12cotx+1−x26x
Cameroon GCE advanced level June 2025 mathematics with statistics 3
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