cameroon gce A level June 2024 further mathematics 1
cameroon gce A level June 2024 further mathematics 1
Twenty units of a chemical is being
dissolved in water. The rate at which
the chemical dissolves is inversely
proportional to the amount, u1. already in
the solution. The differential equation that
describes this situation is
The mean value of y = tanh6 over the D 4
interval0 < Q < ! is
A ln(coshl)
cosh I
23.
The period of the simple harmonic
motion
,represented by the equation
d2x .
1– Ox = 0 , is
30.
BC
0
dt1
D
| A | 3 seconds |
| B | 27T ‘ |
t – 24 r, – /.
— seconds
24. The conic = 1, where t e R,
•
is — seconds
A an ellipse 21r
B a hyperbola
C a parabola
D a rectangular Hyperbola
D ;i7r
— seconds
2
31. Given that the moment of inertia of a
body of mass 1Om about an axis is
48ma2, its radius of gyration about this
The mean value of y = tanh6 over the D 4
interval0 < Q < ! is
A ln(coshl)
cosh I
23.
The period of the simple harmonic
motion
,represented by the equation
d2x .
1– Ox = 0 , is
30.
BC
0
dt1
D
| A | 3 seconds |
| B | 27T ‘ |
t – 24 r, – /.
— seconds
24. The conic = 1, where t e R,
•
is — seconds
A an ellipse 21r
B a hyperbola
C a parabola
D a rectangular Hyperbola
D ;i7r
— seconds
2
31. Given that the moment of inertia of a
body of mass 1Om about an axis is
48ma2, its radius of gyration about this
A particle performs simple harmonic motion 46. Vi – .r ‘2
with maximum speed 4ms’1, Given that its
displacement from the centre is \f7\ m when its
speed is 2ms‘ 1. the angular velocity of the
particle is
the interval 0 < r < – > ,s
<2
2 6/ VS
–2linJTi
lu‘JTi
A
A I
1mils
‘2nuls
l^nnls
‘Ayflrads
ft
c
c I
n
Given that the focus of a parabola is at the
point (3,0), its equation is
| y 2 = 4.v | A |
| ft y = 12A* 2 | |
| C | y 2 = 9A |
| D | v–2 = 12x |
47.
A uniform rod AB of mass m and length 2a
rotates about an axis through A and
perpendicular to the rod. Its moment of inertia
about this axis is;
43.
. A 1
— wn ~
B
— nnr
Given that AB =i+ j,a n d AC = j — k. the
area of the triangle ABC in square units is ;
48.
C
:\ ma2
^ \ riKi – A 3
B
A particle moves round the curve
r = a( 1+sin0 ) with constant angular
velocity ft; . Its radial component of velocity
44
2
C VS
D ‘ VS
IS
2
| aft;sin0 | A |
| B —uco cos0 –u(osin0 C |
|
| D | aco cos0 |
A cyclic group of residue modulo 5 has
generator
49.
A geometric
B arithmetic
C alternating
l) constant
50. The velocities,of a sphere.! of mass m before
and after it collides obliquely with another
sphere B are, respectively (-2i + r>j) ms 1 and
(i f 4j) ms 1. The impulse experienced by B is
A ///(.3i– j)
ft m(:«i –f j)
C – j)
D m( —‘M + j)
S I O P
CIO BACK AND CHECK YOUR WORK
