Advanced level 2025 North West mock Physics guide
Advanced level 2025 North West mock Physics guide
2. a) From graph,
Q0 = 56 Β΅C, 1
2
Q0 = 28 Β΅C, (1) Ξt = π‘1
β2= 9s (1)
b) Q = π0π
-π‘
πΆπ
β
ππ
ππ‘
=
-1
πΆπ
π0π
-π‘
πΆπ
I = – ππ
ππ‘
β I = 1
πΆπ
π0π
-π‘
πΆπ
β I0 = π0
πΆπ
I0 = 56 π₯ 10-6
9 π
πΆ (1) β I0 = 6.2 x 10-6 A (1)
c) C = 18.8 nF, Q0 = CE β E = π0
πΆ
E = 56 π₯ 10-6 πΆ
18.8 π₯ 10-6πΉ (1) β E = 3.0 V (1)
(6 marks)
3. a) the sources
– must be coherent ie same frequency and
should either be in phase or have a constant
phase difference (1)
– very close to each other (1)
b) Ξ» = 480 x 10-9 m, fringe separation y = 25.6 ππ
20
y = 1.28 x 10-3 m, d = 0.4 x 10-3 m but y = ππ₯
π
β
π₯ =
ππ¦
π β π₯ =
0.4 π₯ 10-3 π₯ 1.28 π₯ 10-3
480 π₯ 10-9 m (1)
π₯ = 1.1 π (1)
π) the fringe separation decreases (1)
Ξ»blue < Ξ»green , from y = ππ₯
π
, y Ξ± Ξ» (1)
(6 marks)
4. a) law of conservation of energy (1)
b) -3 correct equations from Kirchoffβs laws
(1) x 3
– solving the equations simultaneously (1)
– current through 18 β¦ resistor = 0.7 A, current
through 5 β¦ resistor = 1.4 A, current through
4 β¦ resistor = 2.1 A (1)
(6 marks)
5. a)
The string breaks when the oject is vertically below the
centre of the circle as then the tension in the string is
maximum (1)
T – mg = ππ£2
π
β π
πππ₯ β mg =
ππ£πππ₯ 2
π
π
πππ₯ = 62 N, m = 200 g = 0.2 kg, r = 80 cm = 0.8 m
Substitution (1), π£πππ₯ = 15.5 ms-1 (1)
b) When the string breaks, the particle becomes a
projectile projected horizontally at a speed of 15.5 ms-1
sy = uyt +
1 2
ayt2; sy = -3 m, uy = 0, ay = – 9.8 ms-2
β time to strike the ground t = 0.8 s (1)
π£ = π’ + ππ‘ β π£π₯ = π’π₯ + ππ₯π‘, ππ₯ =0, β π£π₯= 15.5 ms-1
π£π¦
= π’
π¦ + ππ¦π‘ ; π’π¦= 0, ππ¦ = -π, π‘ = 0.8 π
π£π¦
= (-9.8)(0.8) β π£π¦ = -7.8 ππ -1
v β = [(15.5)π’ – (7.8)π£]ms-1 (1)