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Marking Guide for 0580 Physics Paper 2, 2026

Below is the structured marking guide extracted from the document, organized by section and question number.

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Section I

1.

• a) kWh (1)

• b) Total cost = total energy used x unit cost (1)

  • $1\text{kW} \times 5 \times 30 \times 50$ (1)

  • $7500\text{frs}$ (1)

• c) $P = IV$, $I = 1000/220 = 4.5$ (approx. 5) A (1+1)

2.

• a) Tension in the rope and weight. (1+1)

• b) $w = mg$, $25 \times 10 = 250\text{N}$ (1+1)

• c) Any corresponding difference. (1+1)

• d) Upward support = weight = $250\text{N}$ (1+1)

3.

• a) * Current direction (1)

  • Shape and direction of field (1+1)

• b)

  • i) Cork screw rule or right hand grip rule. (1)

  • ii) By increasing the current (using the rheostat). (1)

4.

• a) Infra-red — visible light — ultraviolet (1+1+1)

• b) * Infra-red: skin, photo diode, etc (1)

  • Ultraviolet: photographic film, photo cell, etc (1)

• c) Any two properties (1+1)

5.

• a) Uniform acceleration (1)

• b)

  • i) $u = d/t = 0.02/0.02 = 1\text{m/s}$ (1)

  • ii) $v = d/t = 0.06/0.02 = 3\text{m/s}$ (1)

• c) $a = \frac{v-u}{t} = \frac{3-1}{0.2} = 10\text{m/s}^2$ (1+1+1)

6.

• a)

  • A — Steam point or upper fixed point: $100^\circ\text{C}$ (1+1)

  • B — Ice point or lower fixed point: $0^\circ\text{C}$ (1+1)

• b) To make it more sensitive: reasonable change in length for a small rise in temperature. (1)

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Section II

7.

• a)

  • i) Definition (1); unit $\text{m/s}^2$ (1)

  • ii) Fall under the influence of gravity only. (1)

  • iii) A workable diagram showing ‘h’ (1+1)

    • Describe how height ‘h’ and time ‘t’ are measured using appropriate instruments. (1+1)

    • Time and height (1)

    • Equation $h = ut + 1/2gt^2$ (1)

    • Any precaution (1)

• b)

  • i) Statement (1); proviso (1)

  • ii) Momentum of rifle = momentum of bullet (1)

    • or $m_r \times v_r = m_b \times v_b$

    • $0.8 \times v_r = 0.02 \times 500$ (1)

    • $V_r = 12.5\text{m/s}$ (1)

• c)

  • i) A — uniform acceleration (1); B — constant speed/velocity (1)

  • ii) 5 seconds

  • iii) $s = d/t = 20/10 = 2\text{m/s}$ (1+1)

• d)

  • i) Definition (1); unit (1)

  • ii) As it moves up external atmospheric pressure drops hence internal pressure pushes outwards (causing the increase in size) (1)

  • iii) Labelled diagram or diagrams (1+1)

    • Any two logical procedure followed (1+1)

    • Observations made (1)

    • Logical explanation of observation (1)

    • Precaution (1)

• e)

  • i) $\rho = m/v$, $m = \rho v$ (1)

    • $1000 \times 1.5 \times 1.5 \times 2$ (1)

    • $= 6750\text{kg}$ (1)

  • ii) $P = F/A = \frac{6750 \times 10}{0.3 \times 0.3 \times 4} = 187500\text{Pa}$ (1+1)

• f)

  • i) A (1)

  • ii) A — copper (any one) (1); B — rubber (1)

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END!