The Ionic Product of Water and pH Scale
Understanding the ionic product of water and the pH scale is essential for grasping acid-base chemistry. Let’s explore these fundamental concepts that form the basis of solution chemistry.
The Ionic Product of Water (Kw)
Definition: The ionic product of water is the product of the concentration of hydrogen ions and hydroxide ions from the self-ionization of water at a given temperature.
Pure Water Behavior
Pure water behaves as both an acid and a base—it is amphoteric or amphiprotic. Water molecules ionize according to the equilibrium:
H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)
Or simply:
H₂O ⇌ H⁺(aq) + OH⁻(aq)
Equilibrium Constant Expression
Applying the equilibrium law:
Kc = [H₃O⁺][OH⁻] / [H₂O]²
Since the concentration of water in its pure state is constant (≈ 55.5 mol/dm³):
Kc[H₂O]² = constant = Kw
Therefore:
Kw = [H⁺][OH⁻]
Value of Kw at Different Temperatures
At 25°C (298K):
- [H⁺] = [OH⁻] = 1×10⁻⁷ mol/dm³
- Kw = (1×10⁻⁷) × (1×10⁻⁷) = 1×10⁻¹⁴ mol²/dm⁶
Important Note: Kw increases with temperature. This means pure water becomes more acidic at higher temperatures.
The pH Scale
Definition: pH is defined as the negative logarithm to the base 10 of the hydrogen ion concentration.
pH = -log₁₀[H⁺] = log(1/[H⁺])
pH Calculations
For Pure Water at 25°C:
Since [H⁺] = [OH⁻] and [H⁺] = 1×10⁻⁷ mol/dm³:
pH = -log(1×10⁻⁷) = 7
Therefore, at 25°C:
- pH = 7 → neutral solution
- pH < 7 → acidic solution ([H⁺] > [OH⁻])
- pH > 7 → alkaline solution ([H⁺] < [OH⁻])
The pOH Scale
Similarly, we can define pOH:
pOH = -log₁₀[OH⁻]
Relationship Between pH and pOH:
Since Kw = [H⁺][OH⁻] = 1×10⁻¹⁴
Taking logarithms:
log(Kw) = log[H⁺] + log[OH⁻]
-14 = -log[H⁺] - log[OH⁻]
-14 = -pH - pOHpH + pOH = 14